Iput the maximum of points
question 1:
a car rental agency rents cars for $26.20 per day plus $0.35 per mile driven. your travel budget is $200. write an inequality that represents the maximum number of miles you can drive during a 1-day rental. show your work.
question 2:
suppose that you are running a concession stand when a person gives you $18 and asks for six drinks and as many hot dogs as the remaining money will buy. if drinks are $1.00 and hot dogs are $1.75, what is the maximum number of hot dogs the person can buy? write an inequality that represents your solution. show your work.

Question 1:

Let X be the number of miles you can drive.

you need to multiply the price per mile by the number of miles and add that to the rental fee.

The total cost has to be less than or equal to the total amount of money you can spend.

The equation is : 0.35X + 26.20 ≤ 200

Question 2:

The cost of the six drinks and the cost of X hot dogs need to be equal to or less than the 18 dollars they gave you.

The cost for the 6 drinks can be simplified to be 6.00

The equation would be:

6.00 + 1.75x ≤ 18

This can be simplified by subtracting the cost of the drinks from both sides:

1.75x ≤ 12

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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