Mathematics, 01.10.2019 21:20 biggiecheese93

When two parallel lines are intersected by a transversal, which pair of angles are always supplementary? select all that apply.

a.
corresponding angles

b.
vertical angles

c.
same-side interior angles

d.
alternate interior angles

e.
alternate exterior angles

f.
same-side exterior angles

Answers: 1

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Answers

Answer from: laylay120

Same-Side Interior Angles and Same-Side Exterior Angles

Answer from: StupidFatChipmunk

C and F

Step-by-step explanation:

We are given that two parallel lines are intersected by a transversal.

We have to find pair of supplementary angles.

Supplementary angle: Two angles whose sum is equal to 180 degrees are called supplementary angles.

Corresponding angles

It is not necessary that sum of corresponding angles is always equal to 180 degrees.Therefore, pair of angles are not always supplementary.

So, it is true.

B.Vertical angles

It is not necessary that sum of vertical angles is always equal to 180 degrees.Therefore, pair of angles are not always supplementary.

So, it is not true.

C.Same- side interior angles.

We know that sum of same side interior angles is always equal to 180 degrees.Therefore, they are always supplementary.

So, it is true.

D.Alternate interior angles

It is not necessary that sum of Alternate interior angles is always equal to 180 degrees.Therefore, pair of angles are not always supplementary.

So, it is not true.

E.Alternate exterior angles

It is not necessary that sum of Alternate exterior angles is always equal to 180 degrees.Therefore, pair of angles are not always supplementary.

So, it is not true.

F.Same side exterior angles

We know that sum of same side exterior angles is always equal to 180 degrees.Therefore, they are always supplementary.

C and F

Answer from: Quest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

Answer from: Quest

we'll this would mean that the dunk tank and the bounce house are the same for 20 hours because the 2 represents that the two activities, and the 20 represents the amount of hours they both are. so with this said, it means that the answer is c. the costs for a dunk tank and bounce house are the same for 20 hours.

c.the costs for a dunk tank and bounce house are the same for 20 hours.

hope this .

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When two parallel lines are intersected by a transversal, which pair of angles are always supplement...