Acertain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster. if a certain passenger is to ride the roller coaster 3 times, what is the probability that the passenger will ride in each of the 3 cars?

2/9

Step-by-step explanation:

certain roller coaster has 3 cars

passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster.

First time a passenger can ride any car p=3/3= 1

Second time the passenger should ride another car p=2/3;

Third time the passenger should ride not the 2 cars he had already driven: p=1/3.

so the probability that the passenger will ride in each of the 3 cars P= 1*2/3*1/3= 2/9

127 passengers

Step-by-step explanation:

THis is 127 passenger because if you add all this up and multiply by 2 then divide by 3 you get 127

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet