An observer 2.5 miles from the launch pad of a space shuttle measures the angle of elevation to the base of the shuttle to be 25◦ soon after lift-off. d observer θ how high is the shuttle at that instant (assuming that the shuttle is still moving vertically)? answer in units of miles.

Height of shuttle at that instant  = 1.17 miles

Step-by-step explanation:

Refer the given figure.

C is the position of rocket and B is the position of observer.

Here we need to find AC, that is the height of shuttle at that instant.

Using trigonometric rules on ΔABC, we have

Height of shuttle at that instant = AC = 1.17 miles

28

step-by-step explanation:

8+8+6+6