Suppose a box contains a double-headed coin, a double-tailed coin, and a conventional coin. a coin is picked at random and flipped; the result is a head. what is the probability it is a double-headed coin let d = event that the coin is double-headed let a = event that the coin shows a head calculate p[d|a] =?

P(D|A)=0.666

Step-by-step explanation:

We will use the tree diagram to understand these probabilities that is attached to the bottom of this answer.

Since there are three coins in the box, the probability of taking one in particular (the double-headed one, which is event D) is one third, which is equal to 0.333

Since the coin showed heads, the probability of it being a double-tailed coin is zero.

The Bayes theorem says that P(D|A) is the multiplication of P(D) and P(A), divided the probability of A happening by any means, happening D or not, which is the sum of all probabilities of A happening:

3333333333333333333333333333333333333333333333

step-by-step explanation:

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !