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a ball is thrown upward and outward from a height of 7 feet. the height of the ball, f(x), in feet, can be modeled by f(x) = -0.3x^2 + 2.1x + 7 where x is the ball's horizontal distance, in feet, from where it was thrown.

what is the maximum height of the ball and how far from where it was thrown does this occur?

max height = 7.5 ft

1.3 ft far

Please check below for the detailed answer

Step-by-step explanation:

Given:

f(x) = −0.3x^2 + 2.1x + 7

a) To obtain the maximum height , find f'(x)

f'(x) = - 0.6x + 0.8 = 0

=> x = 0.8 / 0.6 = 1.33 feet

So f(x) is maximum at a horizontal distance of 1.33 ft

To find the max height , find f(1.33)

f(x) = −0.3x^2 + 2.1x + 7, plug in 1.33 for x

=> f(1.33) = −0.3(1.77) + 0.8(1.33) + 7 = 7.5 ft

So the answer is

Maximum height = 7.5 ft , and 1.3 ft far from where it was thrown.

i really dont know

step-by-step explanation: