Hey, can you factor completely 6x^2+11x-10 as (6x-4)(x-15/6)?

i know the proper way is (3x−2)(2x+5) but i did it this way and want to know if it is correct.

The answer to your question is below

Step-by-step explanation:

Factor completely                          6x² + 11x - 10

1.- Multiply 6 by -10 = -60

2.- Find the prime factors of -60

       -60     2

       -30     2

       -15      3                60 = 2 x 2 x 3 x 5

       -5        5              Combine these numbers so, if add them up give +11

       -1                          and if multiply equals -60.

                                   These numbers are +15 and -4

                                    Instead of writing +11x, in the original equation, write,                

                                    + 15x - 4x.

                                    6x² - 4x + 15x - 10       Factorize like terms

                                    2x(3x - 2) + 5(3x - 2)   Factorize like terms

                                    (3x - 2) (2x + 5).

Sorry, I could not get (6x - 4) (x - 15/6)

30 people weigh 160 pounds or more

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116