In △abc, cd is an altitude, such that ad = bc. find ac, if ab = 3 cm, and cd = 3 cm.

answer !

Let AD=BC=x; then BD = 3-x.

Step-by-step explanation:

Then in right triangle BDC the legs are 2 and 3-x and the hypotenuse is x. Use the Pythagorean Theorem to find the value of x.

Then in right triangle ABC the legs are AC and x and the hypotenuse is 3. Use the Pythagorean Theorem again to find the length of AC.

Altitude has property that it falls at right angle.

So, we use pythagoras theorem it both ΔADC and ΔDBC.

In ΔADC

(AC)² = (AD)² + (DC)²

⇒ (AC)² = x² + 9

and in ΔDBC

(BC)² = (BD)² + (DC)²

⇒ x² = (3 - x)² + 9

Substituting this value of x in (AC)²

We get, (AC)² = (3 - x)² + 9 + 9

This is the method to solve this question.

the line of

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length