One car travels 25 km/h faster than another. in the same time that one goes 120 km, the other goes
220 km. find their speeds.

Speed of first car = 30 km/h and speed of second car = 55 km/h

Step-by-step explanation:

Speed = distance/time

Given: distance travelled by one car = 120 km

Distance travelled by second car = 220 km

Now let speed of first car be x km/h.

∴ Speed of second car = (x + 25) km/h  (∵ One car travels 25 km\h faster than another)

Now, if the time is constant, then ratio of distance to speed of first car will be equal to the ratio of distance to speed of another car. e.g.,

∴ Speed of first car = 30 km/h

Speed of second car = (30 + 25) = 55 km/h.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!