Acar insurance company has determined that 66% of all drivers were involved in a car accident last year. among the 1010 drivers living on one particular street, 3 were involved in a car accident last year. if 1010 drivers are randomly selected, what is the probability of getting 3 or more who were involved in a car accident last year? round to three decimal places.

Our required probability is 0.618.

Step-by-step explanation:

Since we have given that

Probability of all drivers were involved in a car accident last year = 66%

Number of drivers = 10

Number of drivers involved in a car accident = 3

So, probability of drivers involved in car accident is given by

Probability of getting 3 or more who were involved in a car accident is given by

P(X≥3)=1-P(X=0)-P(X=1)-P(X=2)

Here,

So, our equation becomes

P(X≥3)=1-P(X=0)-P(X=1)-P(X=2)

Hence, our required probability is 0.618.

answer: 0+0=0

step-by-step explanation:

that is the only answer that can make 0

0 is its x and y coordinate