Arectangle has a length of 15x and a width of 2x^3+4-2x^2. find the perimeter of the rectangle when the length is 5 feet

The perimeter of the rectangle is 17.70 feet

Step-by-step explanation:

- The perimeter of a rectangle is → P = 2l + 2w → where l is its length

  and w is its width

- A rectangle has a length 15x and a width 2x³ + 4 - 2x²

- We need to find its perimeter when its length is 5 feet

∵ The length of the rectangle is 15x

∵ The length of the rectangle is 5 feet

- Equate the length's expressions

∴ 15x = 5

- Divide both sides by 15

∴

- Now lets find the width of the rectangle

∵ The width of the rectangle = 2x³ + 4 - 2x²

∵

- Substitute the value of x in the expression of the width

∴

∴

∴

∴ feet

∵ l = 5 feet and feet

∵ P = 2l + 2w

∴ P = 2(5) +

∴ P = 10 +

∴ P = 17.70 feet

* The perimeter of the rectangle is 17.70 feet

the answer is 5636.7

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step-by-step explanation: