Carl travelled the 1900 km from his home
in eastern ontario to winnipeg. he
travelled by bus to toronto at an average
speed of 60 km/h and then flew to
winnipeg at an average speed of
100 km/h. his total travelling time was
7h. how many kilometres did he travel
by bus? how far did he travel by airplane?

No solution for the problem

Step-by-step explanation:

- Carl traveled the 1900 km from his home  in Eastern Ontario to

  Winnipeg

- He  traveled by bus to Toronto at an average  speed of 60 km/h

- Then flew to  Winnipeg at an average speed of  100 km/h

- His total travelling time was  7 hours

- We need to find the distance he traveled by bus and by airplane

∵ The total distance he traveled is 1900 km

- If he traveled d km by airplane, then the distance traveled by bus

  is 1900 - d

- The total time is 7 hrs

∴ The time of the bus + the time of the airplane = 7

∵ The time of the bus = the distance by bus ÷ the speed of the bus

∵ The speed of the bus = 60 km/h

∵ The distance by bus = 1900 - d

∴ The time of the bus =

∵ The speed of the airplane = 100 km/h

∵ The distance by airplane = d

∴ The time of the airplane =

∵ The total time = 7 hours

∴

- To cancel the denominator multiply all the terms by 600

∴ 6d + 10(1900 - d) = 4200

∴ 6d + 19000 - 10d = 4200

- Add like terms in the left hand side

∴ -4d + 19000 = 4200

- subtract 19000 from both sides

∴ -4d = -14800

- Divide both sides by -4

∴ d = 3700

∵ d represents the distance traveled by airplane

∴ The distance traveled by airplane is 3700 Km and that is impossible

   because the total distance is 1900 km which is less than this distance,

   and the distance traveled by bus will be - 1800 km

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

i dont have an answer

step-by-step explanation: