3x² - 4x – 8=0
does anyone know how to solve this?

That is a quadratic equation.

It can be solved by using the quadratic formula:

x = (-b +-sqr root b^2 -4*a*c) / 2 *a

In this equation a = -3

b = -4 and c = -8

x = (--4 +- sqr root (-4^2 - 4 * -3 * -8)) / (2 * -3)

x = (4 +- sqr root (16 -96)) / -6

x = 4 +- sqr root (-80) / -6

x1 = (4 +8.94427191 * i)  / -6

x2 =(4 -8.94427191 * i)  / -6

Remember that "i" is the square root of minus 1.

Step-by-step explanation:

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

answer: 4 (:

step-by-step explanation: