In 1970, 11% of americans completed four years of college; 43% of them were women. in 1990, 22% of americans completed four years of college; 53% of them were women (time, jan. 19, 1996). (a) given that a person completed four years 2 of college in 1970, what is the probability that the person was a woman? (b) what is the probability that a woman finished four years of college in 1990? (c) what is the probability that a man had not finished college in 1990?

a)  0.43

b)  0.1166

c)  0.8966

Step-by-step explanation:

Percentage of people that completed 4 yrs college (1970) = 0.11

Women who passed 4 yrs college in 1970 = 43% of those (above)

Percentage of people that completed 4 yrs college (1990) = 0.22

Women who passed 4 yrs college in 1970 = 53% of those (above)

a)

It is already given in the question that of the people that passed college in 1970, 43% were women. This question already says that given that person completed 4 years college, how many are women??

That probability of that is 0.43

b)

Here, it is NOT given that who passed college. They want to know how many are women FROM THE PASSED ONES. So we need to multiply the percentages, 53% of 11%. That is:

0.53 * 0.22 = 0.1166

The probability is 0.1166

c)

We need to find the probability that MAN HAD FINISHED COLLEGE in 1990 and subtract that from 1 (as it is the complement).

Since 53% are women, that means 100% - 53% = 47% is man

Hence, MAN finishing college in 1990 = 0.47 * 0.22 = 0.1034

Subtract that from whole (1):

1 - 0.1034 = 0.8966

The probability is 0.8966

1 3 5

step-by-step explanation:

i took the test: )

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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