What are the solutions of the equation x4-5x2-36=0?

Step-by-step explanation:

x^4 - 5x^2 - 36 = 0

(x^2 - 9)(x^2 + 4) = 0  - factor the left side

(x + 3)(x - 3)(x^2 + 4) = 0 - factor (x^2 - 9 as difference of squares)

x + 3 = 0    x - 3 = 0    x^2 + 4 = 0  Set each factor to 0 if any 0 the left side 0

x = -3         x = 3         x^2 = -4

                                  x = 2i or -2i

The roots are 3, -3, 2i, -2i .

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