![\displaystyle\frac{\sqrt[3]{4b^2}}{\sqrt[3]{2b}}=\sqrt[3]{\frac{4b^2}{2b}}=\sqrt[3]{2b}](/tpl/images/0257/6835/82f05.png)
Rationalize the denominator and simplify:
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Mathematics, 24.09.2019 08:30 yay47
Rationalize the denominator and simplify:
Answers: 2
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