Right triangle abc is located at a (−1, −2), b (−1, 1), and c (3, 1) on a coordinate plane. what is the equation of a circle a with radius segment ac?
(x + 1)2 + (y + 2)2 = 9
(x + 1)2 + (y + 2)2 = 25
(x − 3)2 + (y − 1)2 = 16
(x − 3)2 + (y − 1)2 = 25

answer:

step-by-step explanation:

use the distance formula to find the length of ac

the circle equation is in the format , with the center being at the point (h, k) and the radius being r

ac = 5, so r = 5

the center of circle a is point a, (-1,-2)

plug in these values to the circle equation.

the 4th choice is the correct one

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15