Between 10 pm and 7: 45 am the water level in a swimming pool decreased by 13/16 inch. assuming the constant rate how much did it drop each hour

How much did it drop each hour is 0.08333 inches/hour

First step is to calculate the Decrease

Decrease = 13/16 inches

Decrease=0.8125 inches

Second step is to calculate the time interval

From 10 pm to  7:45 hours will be 9.45 hours

Time interval= (9 + 45/60) hours

Time interval=9.75 hours

Now let determine How much did it drop each hour

0.8125/9.75 inches/hour

=0.08333 inches/hour

Inconclusion How much did it drop each hour is 0.08333 inches/hour

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inches per hour .

Step-by-step explanation:

Between 10 pm and 7:45 am there are 9 hours and 45 minutes i.e. hours

The water level in a swimming pool decreased by amount in hours  = inches

The water level in a swimming pool decreased by amount in 1 hour:

 = inches

 = inches

= inches

= inches

Hence  it drop by inches  each hour .

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3