Asafety regulation requires the height of a guardrail to be 42 inches with an absolute deviation (the difference it can vary) of 3 inches. find the minimum and maximum heights of a guardrail.

The deviation, means from the shortest height to the tallest height can have a difference of 3 inches.

Using 42 as a midpoint, you would subtract half the deviation to find the shortest value and add half the deviation to find the tallest value:

3/2 = 1.5

42 - 1.5 = 40.5

42 + 1.5 = 43.5

Minimum = 40.5 inches.

Maximum = 43.5 inches.

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).