Acircle has center (5,-4) and radius 8. which gives the equation for the circle?

Use (x - h)^2 + (x - k)^2 = r^2.

Note: (h, k) is the center of the circle.

(h, k) = (5, -4). This means h = 5 and k = -4.

Let r = radius

We now plug and chug.

(x - 5)^2 + (y -(-4))^2 = (8)^2

(x - 5)^2 + (y + 4)^2 = 64

Done.

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!