First angle in the triangle is 52 degrees celsius and i need to find the outside and top

In figure,

AC = BC (given)

Since, in a triangle , angles opposite to equal sides are also equal.

Therefore,

b= 52°

Now,

°.° c is exterior angle of triangle.

.°. c = b + 52°

=> c = 52° + 52°

=> c = 104°

Solution:-

-------------

b = 52° & c =104°

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rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225