Write an equation perpendicular to 5x + 3y = -21 that passes through the point (-5, 1).

the desired equation is y = (3/5)x + 4

Step-by-step explanation:

Solving the given 5x + 3y = -21 for 3y yields  3y = -5x - 21.  Dividing all three terms by 3, we get:

y = (-5/3)x - 7, indicating that the given line has slope -5/3.

The slope of a line perpendicular to this y = (-5/3)x - 7 is 3/5, the negative reciprocal of -5/3.

Start with y = mx + b.  Substitute 1 for y, -5 for x and 3/5 for m.  Then:

1 = (3/5)(-5) + b, or

1 = -3 + b.  Then b must be 4, and so the desired equation is y = (3/5)x + 4.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: