find the equation of a parabola with vertex on the y-axis if points p(x1, 0) and r(3, 9) belong the parabola, the area of △pqr is 40.5sq. units, and point q has coordinates (3, 0).

Step-by-step explanation:

If a parabola has its vertex on the y-axis, then its equation is

This parabola passes through the point R(3,9), then

The area of the right triangle PQR is

Find PQ and QR, if

Now,

We get two possible points and

For point

So,

For point

So,

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

its a straight line parallel to the time axis