Problem 2-13 (algorithmic) consider the following linear program: max 2a+10b 2a ≤ 10 2b ≤ 12 4a +4b =28 a, b ≥ 0 a. select the correct graph that shows the feasible region for the problem. b. what are the extreme points of the feasible region? c. select the correct graph that shows the optimal solution for the problem. (show steps)

answer: 40392

step-by-step explanation:

10098 x 4 = 40392

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

d

because parallelagram have all 4 angels the same size dependeing and a rectangle and square are oth parallelogram

i don't think there is enough