will mark brainliest
what are the roots of the equation?
x2=10−3x
enter your answers in the boxes.
x=
or x=

X1=(-3+7)÷2=2---> X1=2-->First root

X2=(-3-7)÷2=-5---> X2= -5-->Second root

Step-by-step explanation:

X^2=-3X+10 you need to change the order of this equation

X^2+3X-10=0---> You do this in order to do BHASKARA

then you do BHASKARA

-3(±√9-4·1·-10)÷2·1

X1=(-3+7)÷2=2---> X1=2-->First root

X2=(-3-7)÷2=-5---> X2= -5-->Second root

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

answer: 414,377,008

step-by-step explanation:

just multiply it