Find the odds against a randomly chosen household having a cat if the probability of the event that a randomly chosen household has a cat is 0.31. the odds against a randomly selected household having a cat are :

We want to know the odds against a randomly chosen house having a cat. If you chose a random house, you have a probability of 0.31 of finding a cat there, then you also have a probability of 0.79 for not finding a cat there.

then the odds against selecting a random house with a cat is 0.79, writing it as a ratio we get 79:100, so in 79 of each 100 houses are cat-less.

i think it's either c or d

step-by-step explanation: the entire question is extremely odd. 04 obviously refers to the interest rate. honestly i will say the answer is c. because the (2 x 12) part would mean it's compounded semiannually. i'll say choose c.

72 is the answer to this problem