The point-slope form of the equation of the line that passes through (-5, -1) and (10,-7) is
what is the
standard form of the equation for this line?
© 2x - 5y = -15
© 2x - 5y = -17
2x + 5y = -15
2x + 5y = -17

2x + 5y = -15

Step-by-step explanation:

First, find the Rate of change [Slope]:

-y₁ + y₂\-x₁ + x₂ = m

1 - 7\5 + 10 = -⅖

Apply the Point-Slope Formula, y - y₁ = m(x - x₁), since we are given points. It does not matter which one you choose. NOTE: All negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY careful inserting the coordinates into the formula with their CORRECT signs:

y + 7 = -⅖(x - 10)

y + 7 = -⅖x + 4

- 7 - 7

y = -⅖x - 3 >> Line in Slope-Intercept Form

Here it is in Standard Form:

y = -⅖x - 3

+⅖x +⅖x

⅖x + y = -3 [We do not want fractions in our Standard Equations, so multiply by the denominator to get rid of it.]

5[⅖x + y = -3]

2x + 5y = -15 >> Line in Standard Form

y + 1 = -⅖(x + 5)

y + 1 = -⅖x - 2

- 1 - 1

y = -⅖x - 3 Line in Slope-Intercept Form

y = -⅖x - 3

+⅖x +⅖x

⅖x + y = -3 [We do not want fractions in our Standard Equations, so multiply by the denominator to get rid of it.]

5[⅖x + y = -3]

2x + 5y = -15 >> Line in Standard Form

** You see? I told you it did not matter which ordered pair you choose because you will always get the EXACT SAME RESULT.

I am joyous to assist you anytime.

step-by-step explanation:

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic