The mean number of bacteria in the single cell of a haemocytometer is 2. let
n be the number of bacteria actually observed in a cell. find:
(i) pr(n = 0)
(ii) pr(n = 3)
(iii) pr(n > 2)

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

-2 is the right

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)