Ajogger runs 140 m due west, then changes direction for the second leg of her run. at the end of the run, she is 374 m away from the starting point at an angle of 20o north of west. what were the length and direction of her second displacement?

The length of her second displacement = 247.12 m.

The direction of her second displacement = 31.24° from west.

Step-by-step explanation:

As per the question,

From the figure as drawn below,

Let the starting point be O. After running 140 m due west, she reached at point A.

∴ OA = 140 m

And At the end of the run, she is 374 m away from the starting point at an angle of 20° north of west.

∴ OP = 374 m

We have to find the distance AP = x.

By using the cosine rule in triangle OAP

After putting the given value, we get

  ∴ x = 247.12 m  

Hence,the length of her second displacement = 247.12 m.

Again,

By using the cosine rule in triangle OAP, we get

After putting the given value, we get

∴ α = 148.759°

Hence, the  direction of her second displacement = 180° - α = 180° - 148.759 = 31.24° from west.

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

mia khalifa

step-by-step explanation: