#5: this graph shows the amount of gas, in ounces, in a lawn mower gas tank, modeled as a function of time. determine whether each statement is true according to the graph. select true or false for each statement.
captionless image
true false
the maximum amount of gas in the gas tank was 60 ounces.
the amount of gas in the gas tank is at a maximum at 0 minutes.
the gas tank will be empty after 60 minutes.
the maximum amount of gas in the gas tank was 60 ounces.
the amount of gas in the gas tank is at a maximum at 0 minutes.
the gas tank will be empty after 60 minutes.
coupon
#6: john has a coupon for 20% off any item in a store. what would the final cost be for an item that originally cost $15 if he uses his coupon? (assume there are no taxes)

5. See below

6. $12

Step-by-step explanation:

5.

Image/Graph attached.

The maximum amount of gas in the gas tank was 60 ounces:

The max amount is at the starting, at t = 0. The y-axis (amount of gas) at that time is at 30, so the max amount is 30, NOT 60.

False.

The amount of gas in the gas tank is at a maximum at 0 minutes:

This is true, because the more you drive, the less gas you have. You have a full tank/max before you start. That's at t = 0 minutes.

True.

The gas tank will be empty after 60 minutes:

The y-axis goes to 0 at t = 60 minutes. That means, after 60 minutes, gas is over. Tank is empty. So this is true.

True.

6.

If something costs $15 and John uses a coupon on that, he will get 20% off of that. The final price would be 20% (0.2) less than the original, $15. We need to find 20% of 15 and then subtract from 15.

20% of 15 = 0.2 * 15 = $3

Now

15 - 3 = $12

#5 False, True, True

#6 $12

Step-by-step explanation:

#5 In the figure attached, the missing picture is shown.

#6 The discount is equal to 20/100 * $15 = $3. Then, John has to pay $15 - $3 = $12

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584