The sum of the digits of a two digit number is 14. the difference between the tens digit and the units digit is 2.
if x is the tens digit and y is the ones digit, which system of equations represents the word problem?
xy= 14 and x - y= 2
x + y = 14 and x - y= 2
x + y = 14 and y - x= 2

see explanation

Step-by-step explanation:

Sum of the 2 digits x and y is 14, thus

x + y = 14

The difference between the tens digit x and the ones digit y is 2, thus

x - y = 2

The system of equations representing the problem is

x + y = 14 → (1)

x - y = 2 → (2)

Add the2 equations term by term to eliminate y

2x = 16 ( divide both sides by 2 )

x = 8

Substitute x = 8 into (1)

8 + y = 14 ( subtract 8 from both sides )

y = 6

The 2 digit number is 86

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: