The sum of the digits of a two digit number is 14. the difference between the tens digit and the units digit is 2.
if x is the tens digit and y is the ones digit, which system of equations represents the word problem?
xy= 14 and x - y= 2
x + y = 14 and x - y= 2
x + y = 14 and y - x= 2

see explanation

Step-by-step explanation:

Sum of the 2 digits x and y is 14, thus

x + y = 14

The difference between the tens digit x and the ones digit y is 2, thus

x - y = 2

The system of equations representing the problem is

x + y = 14 → (1)

x - y = 2 → (2)

Add the2 equations term by term to eliminate y

2x = 16 ( divide both sides by 2 )

x = 8

Substitute x = 8 into (1)

8 + y = 14 ( subtract 8 from both sides )

y = 6

The 2 digit number is 86

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.