Two airplanes are flying in the same direction in adjacent parallel corridors. at time t = 0, the first airplane is 10 km ahead of the second one. suppose the speed of the first plane (km/hr) is normally distributed with mean 550 and standard deviation 9 and the second plane's speed is also normally distributed with mean and standard deviation 535 and 9, respectively. a) what is the probability that after 2 hr of flying, the second plane has not caught up to the first plane? (round your answer to four decimal places.)b) determine the probability that the planes are separated by at most 10 km after 2 hr. (round your answer to four decimal places.)

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!