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Mathematics, 18.09.2019 19:00 20calzoy

Match each function to its domain and range.
s(=)=50–3
s(t)= 4–45
$13)=$+1.5
f(x)=-100
domain and range
function
domain: {0, 1, 3, 5, 6}
range: {-20, -16,-8, 0,4}
domain: {-2, -1,0,3, 4)
range: {-13, -8,-3, 12, 17)
domain: {-4, -2, 0, 2, 4)
range: {-40, -20, 0, 20, 40}
domain: {-3, -2,-1, 2, 6}
range: {0.5, 0, -1.5, 3, 2}

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You know the right answer?
Match each function to its domain and range.
s(=)=50–3
s(t)= 4–45
$13)=$+1.5
...

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