The sum of 3 consecutive integers is is 279. find the integers

92, 93, 94

Step-by-step explanation:

Suppose,

Three consecutive integers would be x, (x+1), (x+2)

so,

x + (x+1) +  (x+2) = 279

⇒ x+x+1+x+2= 279

⇒3x+3 = 279

subtract 3 from both sides

⇒3x = 276  

divide both sides by 3

⇒x =276/3

∴x = 92

so,

The integers are-

92, 93, and 94

Step-by-step explanation: The problem is asking us to find three consecutive integers that have a sum of 279. Three consecutive integers can be represented as followed.

X ⇒ first integer

X + 1 ⇒ second integer

X + 2 ⇒ third integer

Since the sum of our three consecutive integers is 279, we can set up an equation to represent this.

X + X + 1 + X + 2 = 279

We can simplify on the left side of the equation.

3x + 3 = 279

      -3     -3   ← subtract 3 on both sides

3x = 276

÷3     ÷3   ← divide both sides by 3

X → 92

X + 1 → 93

X + 2 → 94

Therefore, our three consecutive integers are 92, 93, and 94.

-4

step-by-step explanation:

what "following statement"?

step-by-step explanation: