In this problem, we will find the volume of a solid with circular base of radius 22, for which parallel cross-sections perpendicular to the base are squares. to do this, we will assume that the base is the circle x2+y2=4x2+y2=4, so that the solid lies between planes parallel to the xx-axis at x=2x=2 and x=−2x=−2. the cross-sections perpendicular to the xx-axis are then squares whose bases run from the semicircle y=−4−x2√y=−4−x2 to the semicircle y=4−x2√y=4−x2.

last option: rhombus or kite

step-by-step explanation:

a kite and rhombus have the same shape. as we don't have any specific formula for the calculation of area of kite. the diagonals are used to calculate the area of a kite or rhombus.

the formula for area of rhombus is given by:

here, d_1 is the first diagonal and d_2 is the second diagonal.

so,

last option is the correct answer ..

answer:

step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

7

step-by-step explanation: