Acompany can produce a toy bear at a cost of $5 per bear. when the company sells the bears at a price of $34, they can sell 560 bears each week. it is estimated that for every $0.50 decrease in the price, they can sell 20 more bears. find the price that will maximize the profit for the company.

$290

Step-by-step explanation:

Costing price of a toy bear = $5.00

Selling price of a toy bear = $34.00

Profit comes from each toy bear = 34.00 - 5.00

                                                      = $29.00

Company can sell the number of toy bears each week = 560

The profit for the week = 560 × 29.00 = $16,240

If the company decrease $0.50 in the price.

The new price would be = $34.00 - $0.50

                                         = $33.50

The profit from each bear = 33.50 - 5.00 = $28.50

They can sell 20 more bears.

Now the number of sale of bears = 560 + 20

                                                        = 580

Now the profit for the week = 580 × 28.50

                                              = $16,530

The price that will maximize the profit = 16,530 - 16240

                                                                   = $290

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.