How do you find the value of n in a geometric progression?

A geometric progression is also known as a geometric sequence.

Here is a video explaining how you find the n term value.

https://youtu.be/pwUdYEwT9kY

Hope this helps!

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a