Fernando invested money in a 3–yr cd (certificate of deposit) that returned the equivalent of 3.8% simple interest. he invested $1000 less in a 6–month cd that had a 2% simple interest return. if the total amount of interest from these investments was $424.00, determine how much was invested in each cd.

The amount invested at 3–yr CD was $3,600 and the amount invested at 6–month CD was $2,600

Step-by-step explanation:

Let

x -----> the amount invested at 3–yr CD

x-$1,000 ----> the amount invested at 6–month CD

we know that

The simple interest formula is equal to

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

3–yr CD

substitute in the formula above

6–month CD

substitute in the formula above

Remember that

the total amount of interest from these investments was $424.00

so

substitute and solve for x

therefore

The amount invested at 3–yr CD was $3,600 and the amount invested at 6–month CD was $2,600

i believe a. 12x≥120 is the answer

answer: the proof is mentioned below.

step-by-step explanation:

since, given:   lines bc = ef

prove:   lines ac > ef

          statements                                           reason

1. bc=ef                                           1. given

2. ac= ab+bc                                 2. because b is the point between the  

                                                            line segment ac

3.   ac > bc                                       3. because if a line segment is equal to

                                                          the sum of two line segments then it is

                                                          always greater then each of these

                                                          individual line segments

4. ac > ef                                         4. by equality property.