As shown in class what molar rity of nact would set up and solve for x: (cross multiply) s solation so as to be torie wect an 300 mosm try this on your own, wwn, then read on. show work here on. show work you should have an answer of 0.15 m. if you don't: ask for . you need to calculation for the next part. now find the number of grams per liter needed to make such a solution, using the molecular weight ofnaci (see previous section for this) and the molarity of 0.15 m. take this number and divide by 1000 (this gives grams per milliter (giml). ious r the % of ohne in 100 ml) ren en p section on expressing concentration of a solution as a percent solution if you're not sure why you'e doing this. this calculation gives the % onci in a 100 ml solution with a molarity of 0.15 m. multiple that by 100 (this give the grams per 100 ml this percent of naci is isotonic to the extracellular fluid. (alternatively, use the equality ofgl into g/1000m and then a ratio to find groom l %2 tions now use these same fos stig 1. the pentose ribose has the molecular formula of cshnos irc-12.001: h- 1.008; and o-15,999: calculate the molecular weight to the 100h's place. given that sugars stay in one piece in solution, calculate the molarity, grams per liter and percent sohution ribo an