Asolution initially contains 200 bacteria. 1. assuming the number y increases at a rate proportional to the number present, write down a differential equation connecting y and the time t. 2. if the rate of increase of the number is initially 100 per hour, how many bacteria are there after 2 hours? solution:

1.

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

=Number of bacteria per unit time

Where k=Proportionality constant

2.,y'(0)=100

Integrating on both sides then, we get

We have y(0)=200

Substitute the values then , we get

Substitute the value of C then we get

Differentiate w.r.t

Substitute the given condition then, we get

Substitute t=2

Then, we get

e=2.718

Hence, the number of bacteria after 2 hours=543.6

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

sorry not sure

step-by-step explanation: