In the card game of poker, five cards that have consecutive kinds is called a straight.
an ace can be considered either the lowest card of an a-2-3-4-5 straight or the highest card of a 10-
j-q-k-a straight. what is the probability that a five-card poker hand contains a straight? for this
problem, you may consider a suited straight (all cards of the same suit) as a straight although the rules
of poker exclude that as a straight.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

whatvare the choices

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

answer: i think one of the answer is $150 and $300?

step-by-step explanation: