Two cars leave a city heading in the same direction. after 3 hours, the faster card is 9 miles ahead of the slower car. the slower car has traveled 153 miles. find the speed of the two cars.

The speed of the slower car is: 51 miles/hour and the speed of the faster car is 54 miles/hour.

Step-by-step explanation:

First, we can easily find the speed of the slower car, since we know that the speed is given by the formula v=d/t, where d stands for the traveled distance and t for the elapsed time.

Next, for the faster car, we know that the distance traveled is 153+9 miles in the same time, therefore, its speed is given by:

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step-by-step explanation: