Mathematics, 13.09.2019 19:30 123martinnnnn

On a coordinate plane, parallelogram p q r s is shown. point p is at (negative 2, 5), point q is at (2, 1), point r is at (1, negative 2), and point s is at (negative 3, 2). in the diagram, sr = 4 startroot 2 endroot and qr = startroot 10 endroot. what is the perimeter of parallelogram pqrs? startroot 10 endroot units 8 startroot 2 endroot + 2 startroot 10 endroot units 16 startroot 2 endroot units 8 startroot 2 endroot + 8 units

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Answer from: pennygillbert

The perimeter of parallelogram PQRS = $2\sqrt{10}+8\sqrt{2}$ ⇒

2nd answer

Step-by-step explanation:

* Lets revise some properties of the parallelogram

- Each two opposite sides are parallel

- Each two opposite sides are equal

- Its perimeter is the twice the sum of two adjacent sides

* Lets solve the problem

∵ PQRS is a parallelogram

∵ The length of side SR is $4\sqrt{2}$

∵ The length of side QR is $\sqrt{10}$

∵ SR and RQ are two adjacent sides

∵ The perimeter of parallelogram PQRS = 2(RQ + SR)

∴ The perimeter of parallelogram PQRS = $2(\sqrt{10}+4\sqrt{2})$

∵ $2*\sqrt{10}$ = $2\sqrt{10}$

∵ $2*4\sqrt{2}$ = $8\sqrt{2}$

∴ The perimeter of parallelogram PQRS = $2\sqrt{10}+8\sqrt{2}$

Answer from: itsyogirl12

The required perimeter of parallelogram PQRS is $8\sqrt{2} + 2\sqrt{10}$ units.

Given that,

On a coordinate plane, parallelogram PQRS,

There points are P is at (-2, 5), point Q is at (2, 1), point R is at (1, -2), and point S is at (-3, 2),

Length of SR = $4\sqrt{2}$ and QR = $\sqrt{10}$ .

We have to find,

The perimeter of parallelogram PQRS.

According to the question,

The properties of the parallelogram is each two opposite sides are parallel and each two opposite sides are equal.

Its perimeter is the twice the sum of two adjacent sides

Then, PQRS is a parallelogram,

SR and RQ are two adjacent sides,

The perimeter of parallelogram PQRS = 2(RQ + SR)

The perimeter of parallelogram PQRS = $2 ( 4\sqrt{2} + \sqrt{10} )$

The, The perimeter of parallelogram PQRS = $8\sqrt{2} + 2\sqrt{10}$ .

Hence, The required perimeter of parallelogram PQRS is $8\sqrt{2} + 2\sqrt{10}$ units.

For the more information about Parallelogram click the link given below.

link.

Answer from: Quest

The answer is a good luck
Ineed to pass this math test today !

Answer from: Quest

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 = $6^{2}$

x = 3, y = 216 = $6^{3}$

x = 4, y = 1296 = $6^{4}$

x = 5, y = 7776 = $6^{5}$

so, the geometric series obtained is $6, 6^{2}, 6^{3}, 6^{4}, 6^{5}$ .

thus, the common ratio is given by $\frac{6^{2}}{6}$ = $\frac{36}{6}$ = 6.

hence, the common ratio is 6.

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On a coordinate plane, parallelogram p q r s is shown. point p is at (negative 2, 5), point q is at...