The prophylactic dose of riboflavin is 2 mg. how many micrograms of riboflavin are in a multiple vitamin capsule containing 1/5 of the prophylactic dose?

There are 400 micrograms of riboflavin in a multiple vitamin capsule containing 1/5 of the prophylactic dose

Step-by-step explanation:

First step: How many mg of riboflavin are there in the capsule?

This can be solved as a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

In this step, the measures are:

-The percentage of the dose.

-The number of mg of the dose.

As one measure increases, so do the other. It means that we have a direct rule of three.

One dose has 2mg. How many mg are in of the dose.

1dose - 2mg

0.2dose - x

x = 2*0.2

x = 0.4mg

Final step: Converting 0.4mg to micrograms.

Unit conversion is an example of a direct rule of three. Each mg has 1000 micrograms, so.

1mg - 1000 micrograms

0.4mg - x micrograms

x = 1000*0.4

x = 400 micrograms

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

correct answer is b. 27/8

step-by-step explanation: