Solve the equation for y(x-3)^=4y-12

First 

y(x + -3) = 4y + -12\

Then you would Reorder the terms:
y(-3 + x) = 4y + -12 (-3 * y + x * y) = 4y + -12
 
And theses (xy + -3y) = 4y + -12(xy + -3y) = 4y + -12

then we would Reorder the terms:xy + -3y = -12 + 4y

then you would Move all terms containing x to the left, all other terms to the right.

so that means we would Add '3y' to each side of the equation.xy + -3y + 3y = -12 + 4y + 3y

then you would want to Combine like terms: -3y + 3y = 0xy + 0 = -12 + 4y + 3y xy = -12 + 4y + 3y
Combine these two 4y + 3y = 7yxy = -12 + 7y
then we would want to Divide each side by 'y'.x = -12y-1 + 7

so after simplifying it, it would be x = 7 + -12y-1