Aline segment with points p(1 2) and q(4 3) is reflected across the line y=x. what are the new coordinates of the points of the line segment? show work!

The new coordinates of the points of the line segment are p'(2,1) and q'(3,4)

Step-by-step explanation:

we know that

When you reflect a point across the line y= x, the x-coordinate and y-coordinate change places.

so

The rule of the reflection of a point across the line y=x is

(x,y) > (y,x)

we have

Points p(1,2) and q(4,3)

Applying the rule of the reflection across the line y=x

p(1,2) > p'(2,1)

q(4,3) > q'(3,4)

therefore

The new coordinates of the points of the line segment are p'(2,1) and q'(3,4)

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

google dat sis

step-by-step explanation: