Apiece of steel bar is 3 ft. long weighed 400 grams. what would be the weight of a piece of the same bar 5 ½ ftm long

0.85% : )

step-by-step explanation:

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x

d secondary market mark brainliest