What are the roots of the equation 2x^2+x=6

(2x - 3)(x + 2)

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

 ( +  x) -  6

Step  2  :

Trying to factor by splitting the middle term

2.1     Factoring  +x-6

The first term is,    its coefficient is  2 .

The middle term is,  +x  its coefficient is  1 .

The last term, "the constant", is  -6

Step-1 : Multiply the coefficient of the first term by the constant   2 • -6 = -12

Step-2 : Find two factors of  -12  whose sum equals the coefficient of the middle term, which is   1 .

     -12    +    1    =    -11

     -6    +    2    =    -4

     -4    +    3    =    -1

     -3    +    4    =    1    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -3  and  4

                    - 3x + 4x - 6

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (2x-3)

             Add up the last 2 terms, pulling out common factors :

                   2 • (2x-3)

Step-5 : Add up the four terms of step 4 :

                   (x+2)  •  (2x-3)

            Which is the desired factorization

(2x - 3)(x + 2)

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

5x+10 is the correct one

hope this