Ahospital claims that the proportion, p, of full-term babies born in their hospital that weigh more than 7 pounds is 36%. in a random sample of 170 babies born in this hospital, 56 weighed over 7 pounds. is there enough evidence to reject the hospital's claim at the level of significance?

Claim :The proportion, p, of full-term babies born in their hospital that weigh more than 7 pounds is 36%.

n =  170

x = 56

We will use one sample proportion test  

The proportion, p, of full-term babies born in their hospital that weigh more than 7 pounds is 36%.

Formula of test statistic =

                                        =−0.8311

Now refer the p value from the z table

P-Value is .202987 (Calculated by online calculator)

Level of significance α = 0.05

Since p value < α

So we reject the null hypothesis .

Hence the claim is true

need more detail

step-by-step explanation:

lele

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.