Usa today reports that ncaa colleges and universities are paying higher salaries to a newly recruited football coach compared to what they paid their previous football coach. (usa today, february 12, 2013). the annual base salaries for the previous head football coach and the new head football coach at 23 schools are given in the datafile coaches..
(a) determine the median annual salary for a previous head football coach and a new head football coach.
(b) compute the range for salaries for both previous and new head football coaches.,
(c) compute the standard deviation for salaries for both previous and new head football coaches.
(d) based on your answers to (a) and (b), comment on any differences between the annual base salary a school pays a new head football coach compared to what it paid its previous head football coach.
coaches
school previous coach's salary new coach's salary
arkansas 850,000 3,200,000
arkansas state 856,210 856,210
auburn 3,500,000 2,300,000
cincinnati 1,769,648 2,200,000
colorado 725,000 2,003,500
florida international 522,183 500,000
idaho 375,797 390,000
kent state 300,000 375,000
kentucky 1,700,000 2,001,250
north carolina state 1,936,225 1,800,000
northern illinoise 420,000 375,000
oregon 3,500,000 1,800,000
purdue 970,000 2,020,000
sa jose state 401,820 525,000
south florida 2,000,000 1,150,000
southern mississippi 790,000 700,000
tennessee 2,000,000 2,960,000
texas tech 2,150,000 2,000,000
texas-el paso 267,800 280,000
western kentucky 475,000 850,000
western michigan 377,250 392,500
wisconsin 2,600,000 1,800,000

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

what is the rest of the question? ?

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.